Monday, February 27, 2012

Fuel economy vs. speed

We all suspect that going faster decreases your fuel economy, and I did an experiment to verify this!


Experimental setup


Car: 2011 VW Golf 2.0L TDI (common-rail Diesel)
Road: I-5 South, between CA-152 and the Tejon Pass
Other notes: outside air temperature = 60°F = 15°C, tire pressure nominal (38 psi).

I took the measurements from the multi-purpose display in the car dashboard. Each point in the plot is an average over at least 3 miles. Most of the points are from about 10 miles. "Drafting" means following behind a large bluff body (i.e. a truck or a bus) at a distance of 200-300 feet.

I used liters per 100 km for the primary axes (for good reasons), but on the right I have also labeled the equivalent miles per gallon for reference (to ease your transition to the superior L/100km scale).

First-principles model


The blue line in the plot is predicted from published parameters, so it's pretty cool that it matches the experimental results so well!

First I estimated the total drag forces acting on the car as a function of speed. This includes aerodynamic drag (using CD = 0.32 as specified on VW's website) and rolling resistance (using CRR = 0.010, which seemed typical for car tires). For a given vehicle speed, I used the tire diameter and the gear ratio (from VW's website) to determine engine speed and torque, then used engine displacement to get BMEP (brake mean effective pressure, a measure of volume-specific engine output). These results are shown in the figure below.


For reference, this Golf's maximum torque is 236 ft*lb and its maximum BMEP is 20 atm, so at 70 mph we are operating at 1/3 load.

Then I looked this up on a BSFC map (I found it on an Internet forum, but the axes are in German so it looks legit) to determine the engine efficiency at that operating point and converted1 into appropriate units to produce the top figure.

Cars typically operate in a regime where efficiency improves with engine load, and this is no exception: we go from an LHV efficiency2 of 33% at 50 mph to 40% at 90 mph. This is why our distance-specific fuel consumption (top figure) only increases 2× from 50 to 90 mph even though the drag force (bottom figure) increased 2.5×.


1Using  ρfuel = 0.85 kg/L.
2LHV efficiency is (power output) / (LHV × rate of fuel consumption) where the LHV is a measure of the energy content of the fuel. This is a commonly used efficiency metric and is a decent proxy for thermodynamic efficiency when compared across similar fuel and engine types.

1 comment:

  1. Agreement with theory is amazing! Also amazing how linear with speed it looks considering all that v^3 nonsense we hear. I got a similar result (linearity) with regular gas engines Mercedes clk320A and Tahoe 5.8 liter V8 measuring from 55 to 75. At then current gasoline prices I worked out it only paid me a few bucks per hour to drive slower. I should write that up sometime.

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